Mastering Olympiad Mathematics
A collection of intriguing competition level problems for secondary school students.
Showing posts with label
Olympiad Math trigonometry
.
Show all posts
Showing posts with label
Olympiad Math trigonometry
.
Show all posts
Saturday, May 16, 2015
Mathematical Problem Solving Skill
In this blog post, I will show one really insightful method given by one very intelligent U.K. mathematician on how he used his own elegant way to prove that $\tan^2 20^{\circ}+\tan^2 40^{\circ}+\tan^2 80^{\circ}=33$.
He first noticed that
$\tan 3(20^\circ)=\tan 60^\circ=\sqrt{3}$
$\tan 3(40^\circ)=\tan 120^\circ=-\sqrt{3}$
$\tan 3(80^\circ)=\tan 240^\circ=\sqrt{3}$
Read more »
Older Posts
Home
Subscribe to:
Posts (Atom)