Sum the series below:
[MATH]\sum_{n=4}^{999}\dfrac{1}{\sqrt[3]{n^2-2n+1}+\sqrt[3]{n^2+2n+1}+\sqrt[3]{n^2-1}}.[/MATH]
Question 1: Do you think the expression on the denominator can be factored?
Yes.
No.
This is a really rich way to asking problem so we make the students to think deep before simply giving out the answer yes or no so easily.
Showing posts with label common term. Show all posts
Showing posts with label common term. Show all posts
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