Solve $\sqrt{x+16}+\sqrt[4]{x+16}=12$.
For some students, they would think to square the given equation three times to get rid of the fourth root and square root terms:
$\sqrt{x+16}+\sqrt[4]{x+16}=12$
$(\sqrt[4]{x+16})^2=(12-\sqrt{x+16})^2$
$\sqrt{x+16}=144-24\sqrt{x+16}+x+16$
A collection of intriguing competition level problems for secondary school students.
Showing posts with label roots. Show all posts
Showing posts with label roots. Show all posts
Friday, May 29, 2015
Saturday, May 16, 2015
Mathematical Problem Solving Skill
He first noticed that
$\tan 3(20^\circ)=\tan 60^\circ=\sqrt{3}$
$\tan 3(40^\circ)=\tan 120^\circ=-\sqrt{3}$
$\tan 3(80^\circ)=\tan 240^\circ=\sqrt{3}$
Thursday, April 23, 2015
Floor Function Problem...
Solve the following equation:
$\displaystyle \left\lfloor x+\frac{7}{3} \right\rfloor^2-\left\lfloor x-\frac{9}{4} \right\rfloor=16$
Note: $\displaystyle \lfloor x \rfloor$ denotes the largest integer not greater than $x$. This function, referred to as the floor function, is also called the greatest integer function, and its value at $x$ is called the integral part or integer part of $x$.
$\displaystyle \left\lfloor x+\frac{7}{3} \right\rfloor^2-\left\lfloor x-\frac{9}{4} \right\rfloor=16$
Note: $\displaystyle \lfloor x \rfloor$ denotes the largest integer not greater than $x$. This function, referred to as the floor function, is also called the greatest integer function, and its value at $x$ is called the integral part or integer part of $x$.
Friday, April 10, 2015
Evaluate $abcd$
Let $a, b, c, d$ be real numbers such that [MATH]a=\sqrt{4-\sqrt{5-a}}[/MATH], [MATH]b=\sqrt{4+\sqrt{5-b}}[/MATH], [MATH]c=\sqrt{4-\sqrt{5+c}}[/MATH] and [MATH]d=\sqrt{4+\sqrt{5+d}}[/MATH]. Calculate $abcd$.
This is one very intriguing problem because I am sure your instinct will tell you, No, please don't multiply all the given four expression out! That is a surest way to get into a big mess if you do that, and there got to be an easy way out for this problem.
This is one very intriguing problem because I am sure your instinct will tell you, No, please don't multiply all the given four expression out! That is a surest way to get into a big mess if you do that, and there got to be an easy way out for this problem.
Labels:
Calculate,
equation,
expand,
polynomial,
quartic,
roots,
square root
Monday, April 6, 2015
(2) Evaluate The Sum Of 1/xy+z-1+1/yz+x-1+1/xz+y-1
Regarding the problem to evaluate:
[MATH]\frac{1}{xy+z-1}+\frac{1}{yz+x-1}+\frac{1}{xz+y-1}[/MATH]
given:
[MATH]\begin{cases}x+y+z=2 \\[3pt] x^2+y^2+z^2=3 \\[3pt] xyz=4 \\ \end{cases}[/MATH]
you might be wondering if the proposed solution is the only way to stab at the problem, or more specifically, if you solved it differently, but in a more tedious or long way, can you be proud of it?
[MATH]\frac{1}{xy+z-1}+\frac{1}{yz+x-1}+\frac{1}{xz+y-1}[/MATH]
given:
[MATH]\begin{cases}x+y+z=2 \\[3pt] x^2+y^2+z^2=3 \\[3pt] xyz=4 \\ \end{cases}[/MATH]
you might be wondering if the proposed solution is the only way to stab at the problem, or more specifically, if you solved it differently, but in a more tedious or long way, can you be proud of it?
Subscribe to:
Posts (Atom)