Given xy≠1, and x and y are the roots of the equations 6x2+2015x+8=0 and 6x2+2015x+8=0 respectively. Evaluate xy.
Solution:
Since the coefficients of 6x2+2015x+8=0 are the same as the coefficients of 8y2+2015y+6 in reversed order, and we're told that x is the root of the equation 6x2+2015x+8=0 while y is the root of the equation 8y2+2015y+6.
Therefore, we have x,1y are the roots of the equation 6x2+2015x+8=0 and hence their product is 86=43.
Suppose we have not realized the reversed order of the coefficients between the two given quadratic equations, we can still manage this problem though the tedious way out, i.e. to solve for both equations for the values of x and y and then find for their product, and bear in mind that xy is a rational number:
Solving 6x2+2015x+8=0 for x, we get:
x=−2015±√20152−4(6)(8)2(6)=−2015±√4,060,0332(6)
Solving 8y^2+2015y+6 for y we get:
\begin{align*}y&=\dfrac{-2015\pm \sqrt{2015^2-4(6)(8)}}{2(8)}\\&=\dfrac{-2015\pm \sqrt{4,060,033}}{2(8)}\end{align*}
Since we're told xy is a rational number, we need to choose wisely for the pair of x and y:
If we pick x=\dfrac{-2015+\sqrt{4,060,033}}{2(6)} then y has to be \dfrac{-2015+\sqrt{4,060,033}}{2(8)} and multiply them together, we get:
\begin{align*}\dfrac{x}{y}&=\dfrac{\dfrac{-2015+\sqrt{4,060,033}}{2(6)}}{\dfrac{-2015+\sqrt{4,060,033}}{2(8)}}\\&=\dfrac{-2015+\sqrt{4,060,033}}{2(6)}\times \dfrac{2(8)}{-2015+\sqrt{4,060,033}}\\&=\dfrac{\cancel{-2015+\sqrt{4,060,033}}}{\cancel{2}(6)}\times \dfrac{\cancel{2}(8)}{\cancel{-2015+\sqrt{4,060,033}}}\\&=\dfrac{4}{3}\end{align*}
and we're done.
Although the second method works, we need to aware that as a 21st century learners, we have to train ourselves to become independent, excellent and QUICK problem solver! We should be passionate about learning new things and to be a critical thinker.
The observation in the first heuristic problem solving method save us great time in tackling this problem successfully and elegantly. The good news is, like I have always said, we can learn the heuristic problem solving skills from others.
Note that this is a problem mentioned here as well:
slideshow-8-creating-curious.
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